Integrand size = 15, antiderivative size = 114 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=\frac {a^7}{b^8 \left (a+b \sqrt {x}\right )^2}-\frac {14 a^6}{b^8 \left (a+b \sqrt {x}\right )}+\frac {30 a^4 \sqrt {x}}{b^7}-\frac {10 a^3 x}{b^6}+\frac {4 a^2 x^{3/2}}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {2 x^{5/2}}{5 b^3}-\frac {42 a^5 \log \left (a+b \sqrt {x}\right )}{b^8} \]
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Time = 0.07 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=\frac {a^7}{b^8 \left (a+b \sqrt {x}\right )^2}-\frac {14 a^6}{b^8 \left (a+b \sqrt {x}\right )}-\frac {42 a^5 \log \left (a+b \sqrt {x}\right )}{b^8}+\frac {30 a^4 \sqrt {x}}{b^7}-\frac {10 a^3 x}{b^6}+\frac {4 a^2 x^{3/2}}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {2 x^{5/2}}{5 b^3} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {x^7}{(a+b x)^3} \, dx,x,\sqrt {x}\right ) \\ & = 2 \text {Subst}\left (\int \left (\frac {15 a^4}{b^7}-\frac {10 a^3 x}{b^6}+\frac {6 a^2 x^2}{b^5}-\frac {3 a x^3}{b^4}+\frac {x^4}{b^3}-\frac {a^7}{b^7 (a+b x)^3}+\frac {7 a^6}{b^7 (a+b x)^2}-\frac {21 a^5}{b^7 (a+b x)}\right ) \, dx,x,\sqrt {x}\right ) \\ & = \frac {a^7}{b^8 \left (a+b \sqrt {x}\right )^2}-\frac {14 a^6}{b^8 \left (a+b \sqrt {x}\right )}+\frac {30 a^4 \sqrt {x}}{b^7}-\frac {10 a^3 x}{b^6}+\frac {4 a^2 x^{3/2}}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {2 x^{5/2}}{5 b^3}-\frac {42 a^5 \log \left (a+b \sqrt {x}\right )}{b^8} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.04 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=\frac {-130 a^7+160 a^6 b \sqrt {x}+500 a^5 b^2 x+140 a^4 b^3 x^{3/2}-35 a^3 b^4 x^2+14 a^2 b^5 x^{5/2}-7 a b^6 x^3+4 b^7 x^{7/2}}{10 b^8 \left (a+b \sqrt {x}\right )^2}-\frac {42 a^5 \log \left (a+b \sqrt {x}\right )}{b^8} \]
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Time = 3.71 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(\frac {\frac {2 x^{\frac {5}{2}} b^{4}}{5}-\frac {3 a \,b^{3} x^{2}}{2}+4 a^{2} x^{\frac {3}{2}} b^{2}-10 a^{3} b x +30 a^{4} \sqrt {x}}{b^{7}}-\frac {14 a^{6}}{b^{8} \left (a +b \sqrt {x}\right )}-\frac {42 a^{5} \ln \left (a +b \sqrt {x}\right )}{b^{8}}+\frac {a^{7}}{b^{8} \left (a +b \sqrt {x}\right )^{2}}\) | \(100\) |
default | \(\frac {\frac {2 x^{\frac {5}{2}} b^{4}}{5}-\frac {3 a \,b^{3} x^{2}}{2}+4 a^{2} x^{\frac {3}{2}} b^{2}-10 a^{3} b x +30 a^{4} \sqrt {x}}{b^{7}}-\frac {14 a^{6}}{b^{8} \left (a +b \sqrt {x}\right )}-\frac {42 a^{5} \ln \left (a +b \sqrt {x}\right )}{b^{8}}+\frac {a^{7}}{b^{8} \left (a +b \sqrt {x}\right )^{2}}\) | \(100\) |
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Time = 0.27 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.38 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=-\frac {15 \, a b^{8} x^{4} + 70 \, a^{3} b^{6} x^{3} - 185 \, a^{5} b^{4} x^{2} - 50 \, a^{7} b^{2} x + 130 \, a^{9} + 420 \, {\left (a^{5} b^{4} x^{2} - 2 \, a^{7} b^{2} x + a^{9}\right )} \log \left (b \sqrt {x} + a\right ) - 4 \, {\left (b^{9} x^{4} + 8 \, a^{2} b^{7} x^{3} + 56 \, a^{4} b^{5} x^{2} - 175 \, a^{6} b^{3} x + 105 \, a^{8} b\right )} \sqrt {x}}{10 \, {\left (b^{12} x^{2} - 2 \, a^{2} b^{10} x + a^{4} b^{8}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 413 vs. \(2 (112) = 224\).
Time = 0.50 (sec) , antiderivative size = 413, normalized size of antiderivative = 3.62 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=\begin {cases} - \frac {420 a^{7} \log {\left (\frac {a}{b} + \sqrt {x} \right )}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {630 a^{7}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {840 a^{6} b \sqrt {x} \log {\left (\frac {a}{b} + \sqrt {x} \right )}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {840 a^{6} b \sqrt {x}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {420 a^{5} b^{2} x \log {\left (\frac {a}{b} + \sqrt {x} \right )}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} + \frac {140 a^{4} b^{3} x^{\frac {3}{2}}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {35 a^{3} b^{4} x^{2}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} + \frac {14 a^{2} b^{5} x^{\frac {5}{2}}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} - \frac {7 a b^{6} x^{3}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} + \frac {4 b^{7} x^{\frac {7}{2}}}{10 a^{2} b^{8} + 20 a b^{9} \sqrt {x} + 10 b^{10} x} & \text {for}\: b \neq 0 \\\frac {x^{4}}{4 a^{3}} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.12 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=-\frac {42 \, a^{5} \log \left (b \sqrt {x} + a\right )}{b^{8}} + \frac {2 \, {\left (b \sqrt {x} + a\right )}^{5}}{5 \, b^{8}} - \frac {7 \, {\left (b \sqrt {x} + a\right )}^{4} a}{2 \, b^{8}} + \frac {14 \, {\left (b \sqrt {x} + a\right )}^{3} a^{2}}{b^{8}} - \frac {35 \, {\left (b \sqrt {x} + a\right )}^{2} a^{3}}{b^{8}} + \frac {70 \, {\left (b \sqrt {x} + a\right )} a^{4}}{b^{8}} - \frac {14 \, a^{6}}{{\left (b \sqrt {x} + a\right )} b^{8}} + \frac {a^{7}}{{\left (b \sqrt {x} + a\right )}^{2} b^{8}} \]
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Time = 0.27 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.89 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=-\frac {42 \, a^{5} \log \left ({\left | b \sqrt {x} + a \right |}\right )}{b^{8}} - \frac {14 \, a^{6} b \sqrt {x} + 13 \, a^{7}}{{\left (b \sqrt {x} + a\right )}^{2} b^{8}} + \frac {4 \, b^{12} x^{\frac {5}{2}} - 15 \, a b^{11} x^{2} + 40 \, a^{2} b^{10} x^{\frac {3}{2}} - 100 \, a^{3} b^{9} x + 300 \, a^{4} b^{8} \sqrt {x}}{10 \, b^{15}} \]
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Time = 5.62 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.95 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^3} \, dx=\frac {2\,x^{5/2}}{5\,b^3}-\frac {\frac {13\,a^7}{b}+14\,a^6\,\sqrt {x}}{b^9\,x+a^2\,b^7+2\,a\,b^8\,\sqrt {x}}-\frac {3\,a\,x^2}{2\,b^4}-\frac {10\,a^3\,x}{b^6}-\frac {42\,a^5\,\ln \left (a+b\,\sqrt {x}\right )}{b^8}+\frac {4\,a^2\,x^{3/2}}{b^5}+\frac {30\,a^4\,\sqrt {x}}{b^7} \]
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